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Graphing Linear Equations

Graphing Linear Equations which are neither in slope-intercept form nor in point-slope form

Often equations are neither in slope-intercept form nor point-slope form. In this case, we can substitute any two different x values, and solve to find the corresponding y values.

Example

Graph 4x + 3y = 24.

Solution

Choose two x values, say x = 0 and x = 2. (We could have chosen any two different x values.) Use substitution to find the corresponding y values.

4x + 3y	= 24
4(0) + 3y	= 24	Replace x with 0.
3y	= 24
y	= 8	Divide each side by 3.

The point at (0, 8) is on the line.

4x + 3y	= 24
4(2) + 3y	= 24	Replace x with 2.
8 + 3y	= 24
3y	= 16	Subtract 8 from each side.
y		Divide each side by 3.

The point at is also on the line.

Graph the line as shown.